## counting_words

### Instructions

In this program you will have to create a function `counting_words` that
receives a `&str` and returns each word and the number of times it appears on the string.

The program will count as a word the following:

- A number like ("0" or "1234") will count as 1.
- A simple word or letter like ("a" or "they") will count as 1.
- Two simple words joined by a single apostrophe ("it's" or "they're") will count as 1.

The program must respect the following rules:

- The count is case insensitive ("HELLO", "Hello", and "hello") are 3 uses of the same word.
- All forms of punctuation have to be ignored except for the apostrophe if used like the example above.
- The words can be separated by any form of whitespace (ie "\t", "\n", " ").

### Expected Function

```rust
fn counting_words(words: &str) -> HashMap<String, u32> {}
```

### Usage

Here is a possible program to test your function :

```rust
use counting_words::counting_words;
use std::collections::HashMap;

fn main() {
    println!("{:?}", counting_words("Hello, world!"));
    println!("{:?}", counting_words("“Two things are infinite: the universe and human stupidity; and I'm not sure about the universe.”
    ― Albert Einstein "));
    println!("{:?}", counting_words("Batman, BATMAN, batman, Stop stop"));
}
```

And its output:

```console
$ cargo run
{"hello": 1, "world": 1}
{"and": 2, "human": 1, "universe": 2, "the": 2, "i\'m": 1, "about": 1, "einstein": 1, "are": 1, "infinite": 1, "sure": 1, "albert": 1, "two": 1, "things": 1, "not": 1, "stupidity": 1}
{"batman": 3, "stop": 2}
$
```