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46 lines
993 B
46 lines
993 B
1 year ago
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## fifthandskip
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### Instructions
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Write a function `FifthAndSkip()` that takes a `string` and returns another `string`. The function separates every five characters of the `string` with a space and removes the sixth one.
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- If there are spaces in the middle of a word, ignore them and get the first character after the spaces until you reach a length of 5.
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- If the `string` is less than 5 characters return `Invalid Input` followed by a newline `\n`.
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- If the `string` is empty return a newline `\n`.
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### Expected function
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```go
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func FifthAndSkip(str string) string {
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}
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```
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### Usage
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Here is a possible program to test your function:
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```go
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package main
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import (
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"fmt"
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"piscine"
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)
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func main() {
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fmt.Print(piscine.FifthAndSkip("abcdefghijklmnopqrstuwxyz"))
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fmt.Print(piscine.FifthAndSkip("This is a short sentence"))
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fmt.Print(piscine.FifthAndSkip("1234"))
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}
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```
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And its output:
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```console
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$ go run . | cat -e
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abcde ghijk mnopq stuwx z$
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Thisi ashor sente ce$
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Invalid Input$
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```
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