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176 lines
3.5 KiB
176 lines
3.5 KiB
5 years ago
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package correct
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type TNode struct {
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Val int
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Left *TNode
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Right *TNode
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}
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func Invert(root *TNode) {
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if root != nil {
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temp := root.Left
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root.Left = root.Right
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root.Right = temp
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Invert(root.Left)
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Invert(root.Right)
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}
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}
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func InvertTree(root *TNode) *TNode {
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Invert(root)
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return root
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}
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type stuNode = TNode
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type solNode = correct.TNode
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func solInsert(N *solNode, newVal int) {
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if N == nil {
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return
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}
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if newVal <= N.Val {
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if N.Left == nil {
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N.Left = &solNode{Val: newVal, Left: nil, Right: nil}
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} else {
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solInsert(N.Left, newVal)
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}
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} else {
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if N.Right == nil {
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N.Right = &solNode{Val: newVal, Left: nil, Right: nil}
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} else {
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solInsert(N.Right, newVal)
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}
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}
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}
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func stuInsert(N *stuNode, newVal int) {
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if N == nil {
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return
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}
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if newVal <= N.Val {
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if N.Left == nil {
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N.Left = &stuNode{Val: newVal, Left: nil, Right: nil}
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} else {
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stuInsert(N.Left, newVal)
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}
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} else {
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if N.Right == nil {
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N.Right = &stuNode{Val: newVal, Left: nil, Right: nil}
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} else {
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stuInsert(N.Right, newVal)
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}
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}
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}
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func IsIdentical(root1 *solNode, root2 *stuNode) bool {
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if root1 == nil && root2 == nil {
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return true
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}
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if root1 == nil && root2 != nil {
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return false
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}
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if root2 == nil && root1 != nil {
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return false
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}
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return root1.Val == root2.Val && IsIdentical(root1.Left, root2.Left) && IsIdentical(root1.Right, root2.Right)
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}
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func stuPrint(w io.Writer, node *stuNode, ns int, ch rune) {
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if node == nil {
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return
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}
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for i := 0; i < ns; i++ {
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fmt.Fprint(w, " ")
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}
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fmt.Fprintf(w, "%c:%v\n", ch, node.Val)
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stuPrint(w, node.Left, ns+2, 'L')
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stuPrint(w, node.Right, ns+2, 'R')
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}
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func solPrint(w io.Writer, node *solNode, ns int, ch rune) {
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if node == nil {
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return
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}
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for i := 0; i < ns; i++ {
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fmt.Fprint(w, " ")
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}
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fmt.Fprintf(w, "%c:%v\n", ch, node.Val)
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solPrint(w, node.Left, ns+2, 'L')
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solPrint(w, node.Right, ns+2, 'R')
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}
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func returnStuTree(root *stuNode) string {
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if root == nil {
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return ""
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}
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ans := strconv.Itoa(root.Val)
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if root.Left == nil && root.Right == nil {
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return ans
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}
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if root.Left != nil {
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ans += " " + returnStuTree(root.Left)
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}
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if root.Right != nil {
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ans += " " + returnStuTree(root.Right)
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}
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return ans
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}
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func returnSolTree(root *solNode) string {
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if root == nil {
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return ""
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}
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ans := strconv.Itoa(root.Val)
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if root.Left == nil && root.Right == nil {
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return ans
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}
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if root.Left != nil {
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ans += " " + returnSolTree(root.Left)
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}
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if root.Right != nil {
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ans += " " + returnSolTree(root.Right)
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}
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return ans
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}
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func main() {
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root, val1, val2, val3, val4 := 0, 0, 0, 0, 0
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root = rand.Intn(30)
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tree := &solNode{Val: root, Left: nil, Right: nil}
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TestTree := &stuNode{Val: root, Left: nil, Right: nil}
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for i := 0; i < 15; i++ {
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tree = &solNode{Val: root, Left: nil, Right: nil}
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temp := tree
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val1, val2, val3, val4 = rand.Intn(30), rand.Intn(30), rand.Intn(30), rand.Intn(30)
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solInsert(tree, val1)
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solInsert(tree, val2)
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solInsert(tree, val3)
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solInsert(tree, val4)
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// solPrint(os.Stdout, tree, 0, 'M')
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correct.InvertTree(tree)
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// solPrint(os.Stdout, tree, 0, 'M')
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TestTree = &stuNode{Val: root, Left: nil, Right: nil}
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tmp := TestTree
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stuInsert(TestTree, val1)
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stuInsert(TestTree, val2)
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stuInsert(TestTree, val3)
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stuInsert(TestTree, val4)
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// stuPrint(os.Stdout, TestTree, 0, 'M')
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InvertTree(TestTree)
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// stuPrint(os.Stdout, TestTree, 0, 'M')
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5 years ago
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if !IsIdentical(tree, TestTree) {
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tree1 := returnSolTree(temp)
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tree2 := returnStuTree(tmp)
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lib.Fatalf("\n\"%v\" instead of \"%v\"\n\n", tree1, tree2)
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// lib.Fatalf("\nError\n\n")
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}
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}
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}
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