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## listreverse
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### Instructions
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Write a function `ListReverse` that reverses the order of the elements of a given linked list `l`.
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### Expected function and structure
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```go
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type NodeL struct {
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Data interface{}
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Next *NodeL
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}
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type List struct {
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Head *NodeL
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Tail *NodeL
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}
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func ListReverse(l *List) {
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}
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```
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### Usage
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Here is a possible [program](TODO-LINK) to test your function :
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```go
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package main
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import (
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"fmt"
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piscine ".."
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)
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func main() {
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link := &piscine.List{}
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piscine.ListPushBack(link, 1)
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piscine.ListPushBack(link, 2)
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piscine.ListPushBack(link, 3)
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piscine.ListPushBack(link, 4)
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piscine.ListReverse(link)
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it := link.Head
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for it != nil {
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fmt.Println(it.Data)
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it = it.Next
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}
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fmt.Println("Tail", link.Tail)
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fmt.Println("Head", link.Head)
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}
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```
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And its output :
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```console
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student@ubuntu:~/piscine/test$ go build
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student@ubuntu:~/piscine/test$ ./test
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4
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3
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2
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1
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Tail &{1 <nil>}
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Head &{4 0xc42000a140}
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student@ubuntu:~/piscine/test$
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```
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