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## listreverse
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### Instructions
Write a function `ListReverse` that reverses the order of the elements of a given linked list `l`.
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### Expected function and structure
```go
type NodeL struct {
Data interface{}
Next *NodeL
}
type List struct {
Head *NodeL
Tail *NodeL
}
func ListReverse(l *List) {
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}
```
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### Usage
Here is a possible program to test your function :
```go
package main
import (
"fmt"
"piscine"
)
func main() {
link := &piscine.List{}
piscine.ListPushBack(link, 1)
piscine.ListPushBack(link, 2)
piscine.ListPushBack(link, 3)
piscine.ListPushBack(link, 4)
piscine.ListReverse(link)
it := link.Head
for it != nil {
fmt.Println(it.Data)
it = it.Next
}
fmt.Println("Tail", link.Tail)
fmt.Println("Head", link.Head)
}
```
And its output :
```console
$ go run .
4
3
2
1
Tail &{1 <nil>}
Head &{4 0xc42000a140}
$
```