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## counting_words
### Instructions
In this program you will have to create a function `counting_words` that
receives a `&str` and returns each word and the number of times it appears on the string.
The program will count as a word the following:
- A number like ("0" or "1234") will count as 1.
- A simple word or letter like ("a" or "they") will count as 1.
- Two simple words joined by a single apostrophe ("it's" or "they're") will count as 1.
The program must respect the following rules:
- The count is case insensitive ("HELLO", "Hello", and "hello") are 3 uses of the same word.
- All forms of punctuation have to be ignored except for the apostrophe if used like the example above.
- The words can be separated by any form of whitespace (ie "\t", "\n", " ").
### Expected Function
```rust
fn counting_words(words: &str) -> HashMap<String, u32> {}
```
### Usage
Here is a possible program to test your function :
```rust
use counting_words::counting_words;
use std::collections::HashMap;
fn main() {
println!("{:?}", counting_words("Hello, world!"));
println!("{:?}", counting_words("“Two things are infinite: the universe and human stupidity; and I'm not sure about the universe.”
― Albert Einstein "));
println!("{:?}", counting_words("Batman, BATMAN, batman, Stop stop"));
}
```
And its output:
```console
$ cargo run
{"hello": 1, "world": 1}
{"and": 2, "human": 1, "universe": 2, "the": 2, "i\'m": 1, "about": 1, "einstein": 1, "are": 1, "infinite": 1, "sure": 1, "albert": 1, "two": 1, "things": 1, "not": 1, "stupidity": 1}
{"batman": 3, "stop": 2}
$
```