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@ -7,7 +7,7 @@ Write a command line in a `skip-lines.sh` file that prints the result of a `ls -
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Example: |
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```console |
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User-> ls -l |
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$ ls -l |
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drwxr-xr-x 16 User User 4096 nov 11 10:55 Desktop |
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drwxr-xr-x 22 User User 4096 nov 4 10:02 Documents |
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drwxr-xr-x 6 User User 4096 nov 11 10:40 Downloads |
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@ -24,24 +24,29 @@ drwxr-xr-x 6 User User 4096 nov 11 10:40 Downloads
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drwxr-xr-x 2 User User 4096 set 29 10:34 Pictures |
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``` |
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**Tips:** |
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### Hints |
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Here are some Commands that can help you: |
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- `sed`. Edit text in a scriptable manner. You can see also: awk. [For more information](https://www.gnu.org/software/sed/manual/sed.html). |
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- `sed`. Edit text in a scriptable manner. |
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- Print just a first line to stdout: |
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`{{command}} | sed -n '1p'` |
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```console |
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User-> cat file |
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$ cat file |
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AIX |
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Solaris |
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Unix |
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Linux |
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HPUX |
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User-> sed -n '1p' file |
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$ sed -n '1p' file |
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AIX |
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``` |
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Use man to see how `awk` or `sed` works, they can do the job. |
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> You have to use Man or Google to know more about commands flags, in order to solve this exercise! |
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> Google and Man will be your friends! |
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### References |
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- [Sed](https://www.gnu.org/software/sed/manual/sed.html). |