public/subjects/fifthandskip

fifthandskip

Instructions

Write a function FifthAndSkip() that takes a string and returns another string. The function separates every five characters of the string with a space and removes the sixth one.

• If there are spaces in the middle of a word, ignore them and get the first character after the spaces until you reach a length of 5.
• If the string is less than 5 characters return Invalid Input followed by a newline \n.
• If the string is empty return a newline \n.

Expected function

func FifthAndSkip(str string) string {

}

Usage

Here is a possible program to test your function:

package main

import (
	"fmt"
	"piscine"
)

func main() {
	fmt.Print(piscine.FifthAndSkip("abcdefghijklmnopqrstuwxyz"))
	fmt.Print(piscine.FifthAndSkip("This is a short sentence"))
	fmt.Print(piscine.FifthAndSkip("1234"))
}

And its output:

$ go run . | cat -e
abcde ghijk mnopq stuwx z$
Thisi ashor sente ce$
Invalid Input$