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miguel
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2 years ago | |
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README.md | 2 years ago |
README.md
Skip lines
Instructions
Write a command line in a skip-lines.sh
file that prints the result of a ls -l
skipping 1 line out of 2, starting with the first one.
Example:
User-> ls -l
drwxr-xr-x 16 User User 4096 nov 11 10:55 Desktop
drwxr-xr-x 22 User User 4096 nov 4 10:02 Documents
drwxr-xr-x 6 User User 4096 nov 11 10:40 Downloads
drwxr-xr-x 2 User User 4096 mar 31 2022 Music
drwxr-xr-x 2 User User 4096 set 29 10:34 Pictures
drwxr-xr-x 2 User User 4096 nov 23 2021 Public
What we want your script to do is:
drwxr-xr-x 16 User User 4096 nov 11 10:55 Desktop
drwxr-xr-x 6 User User 4096 nov 11 10:40 Downloads
drwxr-xr-x 2 User User 4096 set 29 10:34 Pictures
Tips:
Here are some Commands that can help you:
-
sed
. Edit text in a scriptable manner. You can see also: awk. For more information.- Print just a first line to stdout:
{{command}} | sed -n '1p'
- Print just a first line to stdout:
User-> cat file
AIX
Solaris
Unix
Linux
HPUX
User-> sed -n '1p' file
AIX
Use man to see how awk
or sed
works, they can do the job.