public/subjects/FifthAndSkip

FifthAndSkip

Instructions

Write a function FifthAndSkip() that takes a string and returns another one with words of 5 characters and skips the next character followed by newline \n.

• If there is a space in the middle of a word it should ignore it and get the first character until getting to a length of 5.
• If the string less than 5 characters returns "Invalid Output\n"

Expected function

func FifthAndSkip(str string) string {
}

Usage

Here is a possible program to test your function:

package main

import (
	"fmt"
)

func main() {
    fmt.Print(FifthAndSkip("abcdefghijklmnopqrstuwxyz"))
    fmt.Print(FifthAndSkip("This is a short sentence"))
    fmt.Print(FifthAndSkip("1234"))
}

And its output :

$ go run . | cat -e
abcde ghijk mnopq stuwx yz$
Thisi ashor sente ce$
Invalid Output$