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1.8 KiB
1.8 KiB
Top Frequents
Instructions
Given a non-empty array of integers, return the k most frequent elements. Use a hash map and a heap for efficient lookup and retrieval. The returned array should be ordered by appearance frequency first, and if there is a tie in frequency, the element with the smallest index in the original array will appear first.
Expected Class
import java.util.*;
public class TopFrequents {
public List<Integer> findTopKFrequent(int[] nums, int k) {
// Implementation to find the k most frequent elements
}
}
Usage
Here is a possible ExerciseRunner.java
to test your class:
public class ExerciseRunner {
public static void main(String[] args) {
TopFrequents topFrequents = new TopFrequents();
// Test case 1
int[] nums1 = {1, 1, 1, 2, 2, 3};
int k1 = 2;
System.out.println("Top " + k1 + " frequent elements: " + topFrequents.findTopKFrequent(nums1, k1));
// Test case 2
int[] nums2 = {1};
int k2 = 1;
System.out.println("Top " + k2 + " frequent elements: " + topFrequents.findTopKFrequent(nums2, k2));
// Test case 3
int[] nums3 = {4, 1, -1, 2, -1, 2, 3};
int k3 = 2;
System.out.println("Top " + k3 + " frequent elements: " + topFrequents.findTopKFrequent(nums3, k3));
// Test case 4
int[] nums4 = {4, 1, -1, 2, -1, 2, 3};
int k4 = 10;
System.out.println("Top " + k4 + " frequent elements: " + topFrequents.findTopKFrequent(nums4, k4));
}
}
Expected Output
$ javac *.java -d build
$ java -cp build ExerciseRunner
Top 2 frequent elements: [1, 2]
Top 1 frequent elements: [1]
Top 2 frequent elements: [-1, 2]
Top 10 frequent elements: [-1, 2, 4, 1, 3]
$