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1.5 KiB
1.5 KiB
matrix
Instructions
Define a data structure to represent a matrix of any size and implement the basic operations for this. The next steps need to be followed:
-
You can use a 2 dimensional Vec's. We will consider a matrix as a rectangular arrangements of scalars.
-
You have to use the definition of scalars done in the exercise:
lalgebra_scalar
-
Define
new
that returns a matrix of size1 x 1
-
Then define the associated function
identity
that returns the identity matrix of size n -
Finally, define the associated function
zero
that returns a matrix of sizerow x col
with all the positions filled by zeros
Notions
Expected Functions and Structure
pub struct Matrix<T>(pub Vec<Vec<T>>);
impl <T: Scalar<Item = T>> Matrix<T> {
pub fn new() -> Matrix<T> {
}
pub fn zero(row: usize, col: usize) -> Matrix<T> {
}
pub fn identity(n: usize) -> Matrix<T> {
}
}
Usage
Here is a program to test your function.
use matrix::*;
fn main() {
let m: Matrix<u32> = Matrix(vec![vec![0, 0, 0, 0], vec![0, 0, 0, 0], vec![0, 0, 0, 0]]);
println!("{:?}", m);
println!("{:?}", Matrix::<i32>::identity(4));
println!("{:?}", Matrix::<f64>::zero(3, 4));
}
And its output:
$ cargo run
Matrix([[0, 0, 0, 0], [0, 0, 0, 0], [0, 0, 0, 0]])
Matrix([[1, 0, 0, 0], [0, 1, 0, 0], [0, 0, 1, 0], [0, 0, 0, 1]])
Matrix([[0.0, 0.0, 0.0, 0.0], [0.0, 0.0, 0.0, 0.0], [0.0, 0.0, 0.0, 0.0]])
$