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+## fifthandskip
+
+### Instructions
+
+Write a function `FifthAndSkip()` that takes a `string` and returns another `string`. The function separates every five characters of the `string` with a space and removes the sixth one.
+
+- If there is a space in the middle of a word it should ignore it and get the first character until getting to a length of 5.
+- If the `string` is less than 5 characters returns "Invalid Output\n".
+
+### Expected function
+
+```go
+func FifthAndSkip(str string) string {
+
+
+```
+
+### Usage
+
+Here is a possible program to test your function:
+
+```go
+package main
+
+import (
+	"fmt"
+	"piscine"
+)
+
+func main() {
+	fmt.Print(piscine.FifthAndSkip("abcdefghijklmnopqrstuwxyz"))
+	fmt.Print(piscine.FifthAndSkip("This is a short sentence"))
+	fmt.Print(piscine.FifthAndSkip("1234"))
+}
+```
+
+And its output:
+
+```console
+$ go run . | cat -e
+abcde ghijk mnopq stuwx z$
+Thisi ashor sente ce$
+Invalid Output$
+```