public/subjects/devops/skip-lines

Skip lines

Instructions

Write a command line in a skip-lines.sh file that prints the result of a ls -l skipping 1 line out of 2, starting with the first one.

Example:

$ ls -l
drwxr-xr-x 16 User User      4096 nov 11 10:55 Desktop
drwxr-xr-x 22 User User      4096 nov  4 10:02 Documents
drwxr-xr-x  6 User User      4096 nov 11 10:40 Downloads
drwxr-xr-x  2 User User      4096 mar 31  2022 Music
drwxr-xr-x  2 User User      4096 set 29 10:34 Pictures
drwxr-xr-x  2 User User      4096 nov 23  2021 Public

What we want your script to do is:

drwxr-xr-x 16 User User      4096 nov 11 10:55 Desktop
drwxr-xr-x  6 User User      4096 nov 11 10:40 Downloads
drwxr-xr-x  2 User User      4096 set 29 10:34 Pictures

Hints

Here are some Commands that can help you:

• sed. Edit text in a scriptable manner.

  • Print just a first line to stdout: {{command}} | sed -n '1p'

$ cat file
AIX
Solaris
Unix
Linux
HPUX
$ sed -n '1p' file
AIX

You have to use Man or Google to know more about commands flags, in order to solve this exercise! Google and Man will be your friends!

References

• Sed.